Removing 0 values from stacked bar chart.

[Konrad Zdeb]

Hi,

I'm generating a stacked bar chart using the code below. I would like to remove labels with 0 values from the bar.

* -- Stacked bar chart --.
graph bar variables*, ///
    over(laname, sort(1) descending label(labsize(vsmall) angle(90))) ///
    bar(6, bcolor(gray)) ///
    lines(lwidth(thin) lpattern(solid)) ///
    ytitle("% ", size(small) margin(vsmall)) ///
    ylabel(, labsize(vsmall) angle(horizontal) ) ///
    plotregion(lstyle(none)) ///
    lines(lwidth(vthin)) ///
    title("Title", size(medsmall) position(12) margin(vsmall)) ///
    subtitle("{it: Geo}", size(small) position(12)) ///
    caption("{it: Data source: Source}", ///
    size(vsmall)) ///
    note("Note.", size(vsmall)) ///
    stack percent ///
    legend(order( 1 "1" 2 "2" ///
        3 "3" 4 "4" ///
        5 "5" 6 "6") ///
    rows(2) cols(3)  size(vsmall) ///
    position(6) rowgap(.5) region(fcolor(white) lcolor(black))) ///
    blabel(bar, position(center) format(%9.0f) color(black) ///
    orientation(vertical) size(vsmall)) ///
    name(graph, replace)

As a result, I'm getting the chart below:

[Nick Cox]

Sounds like an if condition.

[Konrad Zdeb]

Sounds like an if condition.

It crossed my mind, but I have six variables. Is my understanding correct that I will have to write it in a form var1 != 0 & var2 !=0 ?

---

As a partial solution I coded 0 as missing values for that varlist. The graph looks fine but I don't like this solution as nothing is missing with respect to those variables.

[Nick Cox]

On second thoughts, my first idea won't work and my alternative is your alternative. I don't see the objection. You want no labels, so...