According to my weakivtest my effective F-test statitic is less than critical value of tau being 10%. So, can't reject the null hypothesis that my isntrument is weak. However, according to all other weak instrument test automatically generated with ivreg2 command suggests that my isntrument is strong. Kleibergen-Paap Wald rk F statistic is greater than the critical value Stock-Yogo weak ID test critical values for K1=1 and L1=1.
According to the confidence interval of Anderson-rubin wald test I cab reject the null hypothesis of Ho: B1=0 and orthogonality conditions are valid.
http://economics.mit.edu/files/15326
From what I understand regardless of the strength of the instrument, it is recommended to report Anderson Rubin as it is robust to weak instruments.
"Specifically, in the leading case with a single endogenous regressor, we recommend that researchers judge instrument strength based on the effective F-statistic of Montiel Olea & Pflueger (2013). If there is only a single instrument, we recommend reporting identification-robust Anderson-Rubin confidence intervals. These are efficient regardless of the strength of the instruments, and so should be reported regardless of the value of the first stage F."
Now I am not sure which is this AR Statistic they refer to, the one automatically reported by ivreg2? or the one reported by weakiv command after ivreg2.
According to this http://economics.mit.edu/files/15326 "If there is only a single instrument, we recommend reporting identification-robust Anderson-Rubin confidence intervals."
Is the following Anderson-Rubin Wald test give me the Anderson-Rubin confidence intervals ?
According to the confidence interval of Anderson-rubin wald test I cab reject the null hypothesis of Ho: B1=0 and orthogonality conditions are valid.
http://economics.mit.edu/files/15326
From what I understand regardless of the strength of the instrument, it is recommended to report Anderson Rubin as it is robust to weak instruments.
"Specifically, in the leading case with a single endogenous regressor, we recommend that researchers judge instrument strength based on the effective F-statistic of Montiel Olea & Pflueger (2013). If there is only a single instrument, we recommend reporting identification-robust Anderson-Rubin confidence intervals. These are efficient regardless of the strength of the instruments, and so should be reported regardless of the value of the first stage F."
Now I am not sure which is this AR Statistic they refer to, the one automatically reported by ivreg2? or the one reported by weakiv command after ivreg2.
Code:
weakivtest, level(0.05) (obs=1,954,820) Montiel-Pflueger robust weak instrument test -------------------------------------------- Effective F statistic: 19.810 Confidence level alpha: 5% -------------------------------------------- -------------------------------------------- Critical Values TSLS LIML -------------------------------------------- % of Worst Case Bias tau=5% 37.105 37.105 tau=10% 23.109 23..109 tau=20% 15.374 15.374 tau=30% 9.650 9.650 --------------------------------------------
Is the following Anderson-Rubin Wald test give me the Anderson-Rubin confidence intervals ?
Code:
Underidentification test Ho: matrix of reduced form coefficients has rank=K1-1 (underidentified) Ha: matrix has rank=K1 (identified) Kleibergen-Paap rk LM statistic Chi-sq(1)=5.07 P-val=0.0243 Weak identification test Ho: equation is weakly identified Cragg-Donald Wald F statistic 2.1e+05 Kleibergen-Paap Wald rk F statistic 19.81 Stock-Yogo weak ID test critical values for K1=1 and L1=1: 10% maximal IV size 16.38 15% maximal IV size 8.96 20% maximal IV size 6.66 25% maximal IV size 5.53 Source: Stock-Yogo (2005). Reproduced by permission. NB: Critical values are for Cragg-Donald F statistic and i.i.d. errors. Weak-instrument-robust inference Tests of joint significance of endogenous regressors B1 in main equation Ho: B1=0 and orthogonality conditions are valid Anderson-Rubin Wald test F(1,405)= 37.36 P-val=0.0000 Anderson-Rubin Wald test Chi-sq(1)= 37.38 P-val=0.0000 Stock-Wright LM S statistic Chi-sq(1)= . P-val= .
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