Need help with i.year output in areg

[Maria Sochi]

Hello,
Thanks for all the help I've received through this forum. I wanted to understand why I got 2 rows for the year dummies (one for year=1 and the other with year=0) whenever I use i.year in areg with industry fixed effects. the sample output is shown below. Can anyone help?

	(1)
	r_d
ln_ind_small_5	-0.0247
	(-1.93)
0.yearid1	0
	(.)
1.yearid1	0.767***
	(4.26)
0.yearid2	0
	(.)
1.yearid2	0.935***
	(5.15)
0.yearid3	0
	(.)
1.yearid3	1.284***
	(6.87)
0.yearid4	0
	(.)
1.yearid4	0.473**
	(2.63)
0.yearid5	0
	(.)
1.yearid5	-0.242
	(-1.33)
0.yearid6	0
	(.)
1.yearid6	0.468**
	(2.58)
0.yearid7	0
	(.)
1.yearid7	1.015***
	(5.38)
0.yearid8	0
	(.)
1.yearid8	0.579***
	(3.32)
0.yearid9	0
	(.)
1.yearid9	0.591***
	(3.31)
0.yearid10	0
	(.)
1.yearid10	0.578**
	(3.17)
0.yearid11	0
	(.)
1.yearid11	0.584**
	(3.12)
0.yearid12	0
	(.)
1.yearid12	0.665***
	(3.42)
0.yearid13	0
	(.)
1.yearid13	1.493***
	(6.89)
0.yearid14	0
	(.)
1.yearid14	0.628**
	(3.15)
0.yearid15	0
	(.)
1.yearid15	0.811***
	(4.35)
0.yearid16	0
	(.)
1.yearid16	1.101***
	(5.76)
0.yearid17	0
	(.)
1.yearid17	1.006***
	(5.24)
0.yearid18	0
	(.)
1.yearid18	0.530**
	(2.95)
0.yearid19	0
	(.)
1.yearid19	0.470*
	(2.55)
0.yearid20	0
	(.)
1.yearid20	0.160
	(0.83)
0.yearid21	0
	(.)
1.yearid21	1.209***
	(5.94)
0.yearid22	0
	(.)
1.yearid22	0.634***
	(3.36)
0.yearid23	0
	(.)
1.yearid23	0.771***
	(4.10)
0.yearid24	0
	(.)
1.yearid24	0.645***
	(3.81)
0.yearid25	0
	(.)
1.yearid25	0
	(.)
_cons	6.724***
	(21.58)
N	115737
adj. R-sq	0.648

Thanks in advance.

[Andrew Musau]

It appears that you created the indicators beforehand and then used factor variable notation -i.yearid-. You should leave the year variable as continuous, the factor variable notation will create the indicators.