Dear Statalisters,
I am trying to test for 95% confidence interval calculation (for the extreme point) using the Fieller method. I used a credit risk as a dependent variable and the direct (adjusted lerner) and the squared term (of adjusted lerner)
I managed to read and replicated a paper by (Hirschberg and Lye, 2017) and my results are the following:
Unfortunately, I am not quite familiar with the test, hence I had to replicate the commands. Therefore, I would appreciate your advice and help of how to determent/interpret the following:
1. How I get the 95% confidence interval
2. How I determine the the interval for extreme point
3. Based on the results what should be me interpretation?
I would appreciate if you can advise whether additional commands are required in order to get 95% confidence interval calculation. In the paper which I am analyzing and trying to replicate the author has displayed the following information?
Thank you in advance for your help.
Kind Regards,
Petko Bachvarov
I am trying to test for 95% confidence interval calculation (for the extreme point) using the Fieller method. I used a credit risk as a dependent variable and the direct (adjusted lerner) and the squared term (of adjusted lerner)
I managed to read and replicated a paper by (Hirschberg and Lye, 2017) and my results are the following:
Code:
gen _xx_ = 0 . label var _xx_ "Ratio" . reg llrgl adjlerner adjlerner2 _xx_ , noconstant note: _xx_ omitted because of collinearity Source | SS df MS Number of obs = 3124 -------------+------------------------------ F( 2, 3122) = 430.76 Model | 10.0026565 2 5.00132827 Prob > F = 0.0000 Residual | 36.2479737 3122 .011610498 R-squared = 0.2163 -------------+------------------------------ Adj R-squared = 0.2158 Total | 46.2506302 3124 .014804939 Root MSE = .10775 ------------------------------------------------------------------------------ llrgl | Coef. Std. Err. t P>|t| [95% Conf. Interval] -------------+---------------------------------------------------------------- adjlerner | -.1147687 .0198311 -5.79 0.000 -.153652 -.0758855 adjlerner2 | .1708729 .0164604 10.38 0.000 .1385986 .2031473 _xx_ | 0 (omitted) ------------------------------------------------------------------------------
Code:
. nlcom _b[adjlerner] / _b[adjlerner2], level(95) _nl_1: _b[adjlerner] / _b[adjlerner2] ------------------------------------------------------------------------------ llrgl | Coef. Std. Err. z P>|z| [95% Conf. Interval] -------------+---------------------------------------------------------------- _nl_1 | -.6716614 .0532586 -12.61 0.000 -.7760464 -.5672763 ------------------------------------------------------------------------------
Unfortunately, I am not quite familiar with the test, hence I had to replicate the commands. Therefore, I would appreciate your advice and help of how to determent/interpret the following:
1. How I get the 95% confidence interval
2. How I determine the the interval for extreme point
3. Based on the results what should be me interpretation?
I would appreciate if you can advise whether additional commands are required in order to get 95% confidence interval calculation. In the paper which I am analyzing and trying to replicate the author has displayed the following information?
Code:
This is just an example, just want to understand which figures should be included based on my results 95% confidence interval, Fieller method [0.485; 0.862]
Kind Regards,
Petko Bachvarov
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