Dear Statalisters,
I am trying to test for an inversed U-shaped between credit risk index and adjusted Lerner index(A measure of market power in the banking market).
To test for a U-shaped pattern between edit risk index and adjusted Lerner index I used a random-effects negative binomial model (supported by a Hausman test - xtnberg) including the direct (significant and positive) and the squared term of my Lerner Index. To corroborate this pattern of findings I would like to conduct a Sasabuchi (1980) test for an inverted U-shape, however I am not sure whether the right command was used to perform Sasabuchi test.
Followed by
Any idea on how to interpret these results? Does this mean that since we reject the null hypothesis based on p-value, that we should accept the H1 (direct U-shape) which is confirmed by the regressions (positive coefficient of Lerner^2):
Can you please confirm that this is the way to perform Sasabuchi test or I have to run another/different test in order to get the required result?
Many thanks in advance for your always precious help,
Petko Bachvarov
I am trying to test for an inversed U-shaped between credit risk index and adjusted Lerner index(A measure of market power in the banking market).
To test for a U-shaped pattern between edit risk index and adjusted Lerner index I used a random-effects negative binomial model (supported by a Hausman test - xtnberg) including the direct (significant and positive) and the squared term of my Lerner Index. To corroborate this pattern of findings I would like to conduct a Sasabuchi (1980) test for an inverted U-shape, however I am not sure whether the right command was used to perform Sasabuchi test.
Code:
Fixed-effect (Hausman test - xtnberg) xtnbreg llrgl car adjlerner adjlerner2 insitution ownership_concentration cir deposit_asset loan_asset otherearningassets incomediversity size tier1 fundingragility luqidasset logz gdp_growth inflation crisis_d listed_d, fe
Code:
Lind and Mehlum's procedure for testing U-shaped relationships or Sasabuchi test utest adjlerner adjlerner2, prefix(llrgl)
Code:
My results are the following:
Conditional FE negative binomial regression Number of obs = 3124
Group variable: y Number of groups = 14
Obs per group: min = 223
avg = 223.1
max = 225
Wald chi2(19) = 95.47
Log likelihood = -481.71589 Prob > chi2 = 0.0000
------------------------------------------------------------------------------
llrgl | Coef. Std. Err. z P>|z| [95% Conf. Interval]
-------------+----------------------------------------------------------------
car | .0480899 .3682911 0.13 0.896 -.6737474 .7699271
adjlerner | -5.870174 1.569279 -3.74 0.000 -8.945904 -2.794444
adjlerner2 | 7.036934 1.943191 3.62 0.000 3.22835 10.84552
insitution | -.1541609 .1247337 -1.24 0.216 -.3986344 .0903125
ownership~on | .0115567 .2493661 0.05 0.963 -.4771918 .5003052
cir | .0020299 .002605 0.78 0.436 -.0030758 .0071356
deposit_as~t | .686342 .4698969 1.46 0.144 -.2346389 1.607323
loan_asset | -2.129252 .5312894 -4.01 0.000 -3.17056 -1.087944
otherearni~s | .216634 .346283 0.63 0.532 -.4620682 .8953361
incomedive~y | .142058 .1615877 0.88 0.379 -.174648 .458764
size | .0747654 .039163 1.91 0.056 -.0019926 .1515234
tier1 | .0816059 .2788698 0.29 0.770 -.464969 .6281807
fundingrag~y | .0959053 .4705931 0.20 0.839 -.8264402 1.018251
luqidasset | .860141 .4811945 1.79 0.074 -.082983 1.803265
logz | .0032852 .0652955 0.05 0.960 -.1246917 .1312621
gdp_growth | -5.295671 1.911873 -2.77 0.006 -9.042874 -1.548468
inflation | -.130405 1.155299 -0.11 0.910 -2.39475 2.13394
crisis_d | .0278075 1.120135 0.02 0.980 -2.167616 2.223231
listed_d | .356337 .1745903 2.04 0.041 .0141463 .6985277
_cons | 13.40707 203.6382 0.07 0.948 -385.7164 412.5306
------------------------------------------------------------------------------
. utest adjlerner adjlerner2, prefix(llrgl)
(325 missing values generated)
Specification: f(x)=x^2
Extreme point: .4170974
Test:
H1: U shape
vs. H0: Monotone or Inverse U shape
-------------------------------------------------
| Lower bound Upper bound
-----------------+-------------------------------
Interval | -.1606019 .9939588
Slope | -8.130464 8.11867
t-value | -3.729346 3.42437
P>|t| | .0000977 .0003121
-------------------------------------------------
Overall test of presence of a U shape:
t-value = 3.42
P>|t| = .000312
.
Can you please confirm that this is the way to perform Sasabuchi test or I have to run another/different test in order to get the required result?
Many thanks in advance for your always precious help,
Petko Bachvarov

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