Hello all,
I am trying to testing for omitted variable bias. Specifically, how strong a correlated omitted variable would have to be to overturn the main results using the user-written Impact Threshold of a Confounding Variable (ICTV) package Konfound. I have a non-linear (logit) model with an interaction term.
So the command in Stata for my logit model is:
Then I run Konfound as:
A few questions:
1. Is it correct to use Konfound (ICTV) for a non-linear model? I see some papers originally saying no, but Konfound has an option to specify non-linear models in Stata (non_li(1)) so I am wondering whether this has been updated/changed.
2. Is my code correct for Konfound? I am getting results for just the first variable (firm_size) in the list after running Konfound so not sure how to fix that because the package won't allow interact terms (##).
3. Any other advice would be much appreciated.
I have exhausted the ssc help for Konfound and all web resources so your help is appreciated.
Thank you.
Roger
I am trying to testing for omitted variable bias. Specifically, how strong a correlated omitted variable would have to be to overturn the main results using the user-written Impact Threshold of a Confounding Variable (ICTV) package Konfound. I have a non-linear (logit) model with an interaction term.
So the command in Stata for my logit model is:
Code:
logit treat firm_size##firm_performance, nolog
Code:
konfound firm_size firm_performance, sig(.05) non_li(1)
1. Is it correct to use Konfound (ICTV) for a non-linear model? I see some papers originally saying no, but Konfound has an option to specify non-linear models in Stata (non_li(1)) so I am wondering whether this has been updated/changed.
2. Is my code correct for Konfound? I am getting results for just the first variable (firm_size) in the list after running Konfound so not sure how to fix that because the package won't allow interact terms (##).
3. Any other advice would be much appreciated.
I have exhausted the ssc help for Konfound and all web resources so your help is appreciated.
Thank you.
Roger
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