Dear all,
I need some advice relative to the choice between nbreg and zinb.
My dependent variable is the number of patent registered by companies (N=200). About 50% of the sample have no registered patent. The mean is 1.86 and sd=4.71.
This indication of overdispersion is confirmed by a significant alpha (LR test of alpha=0: chibar2(01) = 196.74 Prob>=chibar2 = 0.000).
According to the Vuong test ( z =1.98 Pr>z = 0.0237), the zero-inflated NB is more appropriate. AIC and BIC also confirm the conclusion of the Vuong test
NBREG: AIC=660.345 BIC= 693.575
ZINB: AIC=649.385 BIC= 689.261.
At the same time, Desmarais and J. J. Harden. (2013) suggest that the Vuong test needs some correction (*). Applying their proposed correction with the command "zinbcv" (**), I have to choose the standard negative binomial as indicated by the AIC and BIC
Vuong test of zinb vs. standard negative binomial: z = 2.04 Pr>z = 0.0208
Pr<z = 0.9792
with AIC (Akaike) correction: z = 1.27 Pr>z = 0.1027
Pr<z = 0.8973
with BIC (Schwarz) correction: z = -0.02 Pr>z = 0.5068
Pr<z = 0.4932
Would you tell me which test should I follow: the usual Vuong test or the corrected one?
Thank you in advance.
Andry
(*) Testing for zero inflation in count models: Bias correction for the Vuong test
B. A. Desmarais and J. J. Harden. 2013.
Stata Journal Volume 13 Number 4.
(**) package st0319 from http://www.stata-journal.com/software/sj13-4
I need some advice relative to the choice between nbreg and zinb.
My dependent variable is the number of patent registered by companies (N=200). About 50% of the sample have no registered patent. The mean is 1.86 and sd=4.71.
This indication of overdispersion is confirmed by a significant alpha (LR test of alpha=0: chibar2(01) = 196.74 Prob>=chibar2 = 0.000).
According to the Vuong test ( z =1.98 Pr>z = 0.0237), the zero-inflated NB is more appropriate. AIC and BIC also confirm the conclusion of the Vuong test
NBREG: AIC=660.345 BIC= 693.575
ZINB: AIC=649.385 BIC= 689.261.
At the same time, Desmarais and J. J. Harden. (2013) suggest that the Vuong test needs some correction (*). Applying their proposed correction with the command "zinbcv" (**), I have to choose the standard negative binomial as indicated by the AIC and BIC
Vuong test of zinb vs. standard negative binomial: z = 2.04 Pr>z = 0.0208
Pr<z = 0.9792
with AIC (Akaike) correction: z = 1.27 Pr>z = 0.1027
Pr<z = 0.8973
with BIC (Schwarz) correction: z = -0.02 Pr>z = 0.5068
Pr<z = 0.4932
Would you tell me which test should I follow: the usual Vuong test or the corrected one?
Thank you in advance.
Andry
(*) Testing for zero inflation in count models: Bias correction for the Vuong test
B. A. Desmarais and J. J. Harden. 2013.
Stata Journal Volume 13 Number 4.
(**) package st0319 from http://www.stata-journal.com/software/sj13-4
Comment