creating a variable from multiple values in a condition

[Emile Motanda]

Hello everyone, I am new here. I intend to create a new variable (say X) conditioned on the values of four other binary variables (A, B, C, D).
X will range from1 to 16, as in the above table. For instance X = 1 if A=1, B=1, C=1 and D=1 simultaneously. I would appreciate it if someone could tell me how to do it.
With sincere appreciation

A	B	C	D		x
1	1	1	1		1
0	1	1	1		2
1	0	1	1		3
1	1	0	1		4
1	1	1	0		5
0	0	1	1		6
0	1	0	1		7
0	1	1	0		8
1	0	0	1		9
1	0	1	0		10
1	1	0	0		11
1	0	0	0		12
0	1	0	0		13
0	0	1	0		14
0	0	0	1		15
0	0	0	0		16

[Andrew Musau]

egen wanted= group(A B C D)

will map a combination to a value between 1-16 (not necessarily that 1 1 1 1 will be mapped to 1). The same combinations will be mapped to the same number.

[William Lisowski]

If you actually want the exact results shown in post #1 the following will do it.

// read your example data
* Example generated by -dataex-. For more info, type help dataex
clear
input byte(a b c d x)
1 1 1 1  1
0 1 1 1  2
1 0 1 1  3
1 1 0 1  4
1 1 1 0  5
0 0 1 1  6
0 1 0 1  7
0 1 1 0  8
1 0 0 1  9
1 0 1 0 10
1 1 0 0 11
1 0 0 0 12
0 1 0 0 13
0 0 1 0 14
0 0 0 1 15
0 0 0 0 16
end

// generate want to equal your x
generate want1 = 1*a + 2*b + 4*c + 8*d
recode want1 (15=1) (14=2) (13=3) (11=4) (7=5)  (12=6) (10=7) (6=8) ///
             (9=9)  (5=10) (3=11) (1=12) (2=13) (4=14) (8=15) (0=16), generate(want)
list, clean

. list, clean

       a   b   c   d    x   want1   want  
  1.   1   1   1   1    1      15      1  
  2.   0   1   1   1    2      14      2  
  3.   1   0   1   1    3      13      3  
  4.   1   1   0   1    4      11      4  
  5.   1   1   1   0    5       7      5  
  6.   0   0   1   1    6      12      6  
  7.   0   1   0   1    7      10      7  
  8.   0   1   1   0    8       6      8  
  9.   1   0   0   1    9       9      9  
 10.   1   0   1   0   10       5     10  
 11.   1   1   0   0   11       3     11  
 12.   1   0   0   0   12       1     12  
 13.   0   1   0   0   13       2     13  
 14.   0   0   1   0   14       4     14  
 15.   0   0   0   1   15       8     15  
 16.   0   0   0   0   16       0     16