[William Lisowski]

Luther Koch

Welcome to Statalist.

Please note that as discussed above, permutations are different than combinations. If you have 5 variables, each of which can take on one of two values, then you have 2^5 = 32 possible combinations, and permutations don't enter into the picture. This doesn't affect Carole's code, but should affect your expectations of the results.

[Luther Koch]

Thank you for helping me Carole! I apologize for not using dataex; I'll be sure to use it in the future.

[Luther Koch]

Oh, of course. Thank you kindly for setting me straight!

[Luther Koch]

Carole, your solution performed magnificently! Thank you once again! I am indebted.

[Sharma Manoj]

Hello,

Could anyone help me to generate the data for a combination like the below:

Block	Question set	A1	A2	A3	A4	A5	A6	A7	A8	A9
1	1	1	-1	.	.	.	.	.	.	.
1	1	1	.	-1	.	.	.	.	.	.
1	1	1	.	.	-1	.	.	.	.	.
1	1	1	.	.	.	-1	.	.	.	.

There are 9 blocks and each block with 4 question sets. There are 9 alternatives (A1-A9) with combinations of two alternatives as best (-1) and worst (-1) while others are missing.

Thank you in advance !!